Asatellite orbits the earth in the same direction it rotates in a circular orbit above the equator a distance of 250 km from the surface. by how many seconds per day will a clock on such a satellite run slow compared to a clock on the earth? (compute just the special relativistic effects.)

Clock on the satellite is slower than the one present on the earth = 29.376 s

Given:

Distance of satellite from the surface, d = 250 km

Explanation:

Here, the satellite orbits the earth in circular motion, thus the necessary centripetal force is provided by the gravitation force and is given by:

where

v =  velocity of the satellite

R = radius of the earth = 6350 km = 6350000 m

G = gravitational constant =

M = mass of earth =

Therefore, the above eqn can be written as:

Now, for relativistic effects:

Now,

r = R + 250

Ratio of rate of satellite clock to surface clock:

Clock on the satellite is slower than the one present on the earth:

if you answer my question i will answer yours

the moon affects the earth gravitation ally, causing certain motions of that body and also producing tides in its ocean and atmosphere. the tidal wave in our atmosphere is, however, far too minute to be an effective cause in any known meteorological phenomenon.

explanation: