Returning once again to our table top example of a horizontal mass on a low-friction surface with m = 0.254 kg and k = 10.0 n/m with damping characterized by y = 0.628 (1/s). if fo = 0.5 n, calculate a and d for the following values of w: 0.628 rad/s, 3.14 rad/s, 6.28 rad/s, and 9.42 rad/s.

Explanation:

Given that,

Mass = 0.254 kg

Spring constant [tex[\omega_{0}= 10.0\ N/m[/tex]

Force = 0.5 N

y = 0.628

We need to calculate the A and d

Using formula of A and d

.....(I)

....(II)

Put the value of in equation (I) and (II)

From equation (II)

Put the value of in equation (I) and (II)

From equation (II)

Put the value of in equation (I) and (II)

From equation (II)

Put the value of in equation (I) and (II)

From equation (II)

Hence, This is the required solution.

  distance on the y-axis and time on the x-axis.

explanation:

the instantaneous velocity = change in position/time taken

the slope of the graph should give instantaneous velocity.

  slope of a graph = change in value of y -axis / change in values of x -axis

  comparing both the equations

    change in value of y -axis = change in position

  change in values of x -axis = time taken

so position values should be on the y axis and time values should be on the x axis.

distance on the y-axis and time on the x-axis.

one "light year" is the distance that light travels, through vacuum, in one julian year.   that's 365.25 days, of 24 hours each.