An isotope of californium-252 undergoes a spontaneous fission, producing cesium-135, 3 neutrons, and one other isotope. a) determine the identity of the other isotope produced in the fission, and write out the reaction equation, using full isotopic notation, for example pm → c022 + seag + 2n. b) calculate the amount of mass (in u) lost during this fission. the masses of the three isotopes are: 252.081 626 u (californium), 134.905 978 u (cesium), 113.935 880 u (unknown). maintain a precision of no less than 7 sf as you work. c) calculate the energy (in mev) released by this fission, accurate to 3 sf.

For a: The isotopic symbol of unknown element is

For b: The amount of mass lost during this process is 0.2137730 u.

For c: The energy released in the given nuclear reaction is

Explanation:

In a nuclear reaction, the total mass and total atomic number remains the same.

For the given fission reaction:

Total mass on reactant side = total mass on product side

252 = A + 135 + 3

A = 114

Total atomic number on reactant side = total atomic number on product side

98 = Z + 55 + 0

Z = 43

Hence, the isotopic symbol of unknown element is

We are given:

Mass of = 252.081626 u

Mass of = 1.008665 u

Mass of = 134.905978 u

Mass of = 113.935880 u

To calculate the mass defect, we use the equation:

Putting values in above equation, we get:

Hence, the amount of mass lost during this process is 0.2137730 u.

To calculate the energy released, we use the equation:

(Conversion factor:    )

Hence, the energy released in the given nuclear reaction is