Electric field due to a point charge inside a dielectric medium (eg, glass, water, etc.): how does the expression for the electric field due to a positive point charge change in the presence of a dielectric medium with relative permittivity & ?

Explanation:

The electric field due to a positive charge at a distance is given by

Where, q be the charge on the charged particle and r be the distance between the charged particle and the point where electric field is to be calculated.

If the medium is inserted whose dielectric constant is K , then the electric field becomes

As teh value of K is more than 1, so the value of electric field E' is less than E.

It means when the medium is inserted, the electric field becomes reduced.

hello, i am papaguy.

i have found an answer to your question but use it as information.

information: because weak acids/bases have low concentration of hydrogen ions, the addition of water has a large impact on the ph. 2. a difference in 1 unit is a 10x difference in concentration for example; a liquid with ph of 3 is 10x more acidic than a liquid with a ph of 4. therefore, a liquid with a ph of 3 is stronger.

best of luck!

can be answered using momentum.

momentum = p

p1= mass1 * velocity1

p1 = p2

therefore

p1 = 6kg * 4m/s

p1 = 24kgm/s

p2=m2 * v2

24 kgm/s = 7kg * v2

v2 = 24 kgm/s / 7kg

v2= 3.42 m/s