Asound wave in air has a pressure amplitude equal to 3.92 x 103 n/m2. calculate the displacement amplitude of the wave at a frequency of 9.2 khz. (note: use the 1.20 kg/m3; the speed of sound in air is v 343 m/s. pressure variations ap are measured relative to following values, as needed. the equilibrium density of air is p atmospheric pressure, 1.013 x 105 pa.)

1.65 × 10⁻⁴ m

Explanation:

Displacement amplitude  = A = Δ P / 2πf ρv

= ( 3.92 × 10³) / 2π (9.2 × 10³) (1.20)(343)

= 1.65 × 10⁻⁴ m  

Displacement amplitude is the distance traveled by the wave particle from its equilibrium position.

because growing process had stoped after 4-5 year

false.

explanation:

this statement is false. after falling for 5 seconds, its speed will not be 100 m/s.