An electron in a vacuum is first accelerated by a voltage of 71600 v and then enters a region in which there is a uniform magnetic field of 0.345 t at right angles to the direction of the electron's motion. the mass of the electron is 9.11 x 10-31 kg and its charge is 1.60218 x 10-19 c. what is the magnitude of the force on the electron due to the magnetic field? answer in units of n.

Explanation:

It is given that,

Potential difference,

Magnetic field,

The magnetic field is perpendicular to the direction of motion of electron i.e. the angle between velocity and magnetic filed is 90. We need to calculate the magnitude of the force on the electron due to the magnetic field.

Using the conservation of energy as :

Equation (1) becomes :

So, the force acting on the electron due to this magnetic field is . Hence, this is the required solution.

answer: option c. i.e. electric current flowing “downhill” from the negative electrode to the positive electrode in a battery

explanation:

the water analogy to the circuits define the pipes (water flows) to the electric current. now, we know that the electric current flows from the positive terminal to the circuit (as shown in the diagram attached).

hence, option c is the correct answer.

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