Asphere of radius r carries a charge density p(r) = kr, for r < r. (a) what is the field of the sphere, as a function of r? (b) what is the energy of this configuration?

electric field is  k  / ε × 4

energy  is  πk²   /48ε

Explanation:

given data

radius = R

charge density P(r) = kr

r < R

to find out

field of the sphere and energy

solution

we know that  P(r) = kr

here k is constant

we divide the sphere in many number of parts and we consider element thickness is dr so voulme will be 4πr²dr

so charge will be

dq =  P ( 4πr²)dr

dq =  kr ( 4πr²)dr

take integrate both side

∫dq = 4πk ∫r³ dr

q =  4πk / 4

q = πk

so we apply here gauss law

E×A = q / ε

electric field =  πk  / ε × 4πr²

electric field =  πk  / ε × 4πr²

so electric field =  k  / ε × 4

and

in 2nd part we know

U, energy = energy density × volume

U, energy = (1/2 ×   ε × E²) × (4πr² )

U energy = (1/2 ×   ε × (kr²/4ε)²) × (4πr²)

U, energy = πk² / 8ε

take integrate both side with 0 to U and 0 to R

dU = πk²/8ε dr

U, energy =  πk²/8ε × /6

so energy =   πk²   /48ε

answer: strength i guess

explanation:

5 w for 1hr = 5x60x60 joules=300x60=3000x6=18,000j as total energy conversion. efficiency of bulb needed for radiant to thermal within 18000