An electric field of 8.5x10^5 v/m is desired between two parallel plates each of areas 2500 cm^2 and separated by 0.10 mm of air. what charge must be on each plate?

The charge must be on each plate is .

Explanation:

Given that,

Electric field

Area = 2500 cm²

Distance = 0.10 mm

We need to calculate the potential difference

Using formula of potential difference

We need to calculate the capacitor

Using formula of capacitor

Put the value into the formula

We need to calculate the charge

Using formula of charge

Hence, The charge must be on each plate is .

t2 equal the displacement of the particle over the same time period if t2> t/2? hint: consider a sine wave starting at t1=0, then consider a closing wave starting at t1=0, for your explanatio

the answer is ampere

the ampere is used to measure electricity. an ampere is a unit of electric current equal. a unit of measure for the flow of current in a circuit. one ampere is the amount of current flow provided when one volt of electrical pressure is applied against one ohm of resistance.