Acar of weight 1.8 x 10^4 n is accelerated uniformly from rest by a force of 5.0 x 10^3 n east for 6s. calculate the following for the car the displacement from its original position.

Displacement = 50.04 m

Explanation:

Given,

Weight of car, W = 1.8 × 10⁴ N

Initial Velocity, u = 0

Force, F = 5 × 10³ N (at the East direction)

Time, t = 6s

Let 'd' be the displacement in the position of car in 6 seconds.

Mass of car , m = Weight/Gravity

m = 1.8 × 10⁴ N / 10 m/s²

m = 1.8 × 10³ kg

Now,

Force of car = Mass of car × acceleration of car

So, Acceleration = Force/Mass

Acceleration = 5 × 10³ N/1.8 × 10³ kg

Acceleration = 2.78 m/s²

By using the formula of second equation of motion.

s = ut + 1/2 at²

where, u = 0

So,

s = 1/2 at²

s = 1/2 × 2.78 × 6²

s = 1/2 × 2.78 × 36

s = 50.04 m

Here, s is 'd'. 's' and 'd' both are displacement.

the simple machine has three main features. they are:

fulcrum is the center point or pivot point of the machine. effort is input force/ applied force. load is external force/ output.

the keisha 's machine labels are

x : load

y: fulcrum

z: lever