Asolenoid 27.0 cm long and with a cross-sectional area of 0.600 cm2 contains 440 turns of wire and carries a current of 90.0 a. calculate: (a) the magnetic field in the solenoid; (b) the energy density in the magnetic field if the solenoid is filled with air; (c) the total energy contained in the coil’s magnetic field (assume the field is uniform); (d) the inductance of the solenoid

(A) 0.1842 T (B) (C) 0.2188 J (D)

Explanation:

Length of the solenoid L = 27  cm =0.27 m

Area of cross section

Number of turns N = 440

Current i = 90 A

(A) Magnetic field in the solenoid

(B) The energy density is given by

(C) The total energy contained in the coli magnetic field = energy density ×volume = energy density ×l×A

So the total energy

(D) The energy stored in the inductor is given by

So

the answer is to check all of them! they all apply well at least i think so!

the amount of current in the coil