Aslit of width 0.59 mm is illuminated with light of wavelength 474 nm, and a screen is placed 130 cm in front of the slit. find the widths of the first and second maxima on each side of the central maximum.

width of first and second minima is = 1.022 *10^{-3} m

Explanation:

given details:

slit width =[/ex] \alpha = 0.59*10^{-9} m[/tex]

distance between slit and screen =130 cm =1.30m

we know

silt distance between minima = width of the maximum

distance between minima from central maxima is

distance between the successive minima is given as

           = 1.022 *10^{-3} m

massxgravity x heght=weightxheight= pe

4900=490xh

h=10