Two slits are illuminated by a 363 nm light. the angle between the zeroth-order bright band at the center of the screen and the fourth-order bright band is 14.9 ◦ . if the screen is 170 cm from the double-slit, how far apart is this bright band from the central peak

y = 0.44 m

Explanation:

As we know that path difference on the screen is given as

now for constructive interference we know that

path difference = integral multiple of wavelength

so we have

now for 4th maximum on the screen we can say

here N = 4

L = 170 cm = 1.70 m

also we know

path difference on screen = d

now we have

power out to power in less than 100%

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