Ascaffold of mass 64 kg and length 6.3 m is supported in a horizontal position by a vertical cable at each end. a window washer of mass 85 kg stands at a point 2.0 m from one end. what is the tension in (a) the nearer (relative to the person) cable and (b) the farther (relative to the person) cable?

tension far end 883.055714 N

tension closer 578.634286 N

Explanation:

Given data

scaffold mass m1  = 64 kg

scaffold length L1 = 6.3 m

window washer mass m2 = 85 kg

distance L2 = 2 m

to find out

tension near cable and farther cable

solution

torques at the end farthest

(m1  × g × L1 ) / 2  + (m2  × g × L1- L2 )  = T × L1

T × 6.3 = (64  × 9.81 × 6.3 ) / 2  + (85  × 9.81 × 4.3 )

T = 5563.251 / 6.3

tension = 883.055714 N

and

torques at the other end,

(m1  × g × L1 ) / 2  + (m2  × g × L2 )  = T × L1

T × 6.3 = (64  × 9.81 × 6.3 ) / 2  + (85  × 9.81 × 2 )

T = 3645.396 / 6.3

tension = 578.634286 N

i just did an experiment like this in my science class. also the answer is yes, it will get separated because they are two opposites meaning if they are opposite they can not attract.

hope this .!