Acharge q is placed on the x axis at x = +4.0 m. a second charge q is located at the origin. if q = +75 nc and q = −8.0 nc, what is the magnitude of the electric field on the y axis at y = +3.0 m?

23.1 N/C

Explanation:

OP = 3 m , OQ = 4 m

q = - 8 nC, Q = 75 nC

Electric field at P due to the charge Q is

Electric field at P due to the charge q is

According to the diagram, tanθ = 3/4

Resolve the components of E1 along x axis and along y axis.

So, Electric field along X axis, Ex = - E1 Cos θ

Ex = - 27 x 4 / 5 = - 21.6 N/C

Electric field along y axis, Ey = E1 Sinθ - E2

Ey = 27 x 3 /5 - 8 = 8.2 N/C

The resultant electric field at P is given by

b) phosphorus pentoxide

power out to power in less than 100%