Aball travels on a parabolic path in which the height (in feet) is given by the expression $-16t^2+64t+31$, where $t$ is the time after launch. what is the maximum height of the ball, in feet?

Maximum height, h(t) = 95 meters

Explanation:

A ball travels on a parabolic path in which the height (in feet) is given by :

.............(1)

Where

t is the time after launch

We need to find the maximum height of the ball in feet. For maximum height,

t = 2

Put the value of t in equation (1) as :

h(t) = 95 meters

So, the maximum height of the ball is 95 meters. Hence, this is the required solution.

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