Calculate the momentum of a 1950 kg elephant charging a hunter at a speed of 7.50 m/s. (b) compare the elephant's momentum with that of a 0.0400 kg bullet fired at a speed of 600 m/s. (c) what is the momentum of the 90.0 kg hunter running at 8.00 m/s after missing the elephant?

a) (momentum of the elephant), p1 = 14625 kg×m/s

b) p1 = 609.4×p2

c) (momentum of the hunter), p3 = 720 kg×m/s.

Explanation:

a) if m = 1950 kg is the mass of the elephant and V = 7.50 m/s be the speed of the elephant, then the momentum is given by:

p1 = m×V = (1950)×(7.50) = 14625 kg×m/s

b) if m = 0.0400 kg is the mass of the bullet and v = 600 m/s be the speed of the bullet, then the momentum of the bullet is given by:

p2 = m×v = (0.0400)×(600) = 24 kg.m/s

then:

p1/p2 = (14625)/(24) = 609.4

that is, p1 = 609.4×p2

Therefore, the momentum of the elephant is 609.4 times the momentum of the bullet.

c) the momentum og the hunter after missing the elephant is given by:

p3 = m×v = (90.0)×(8) = 720 kg.m/s

Therefore, the momentum of the hunter is 720 kg×m/s.

explanation:

v=uf/(u-f)

= 5.-10/(5+10) convex lens has negative focal length

r = ρ x length / area  

ρ = r x area / length  

ρ is in ohm-meters  

in basic units, it is m³kg/s³a²  

i think this is it.