Two cars collide on the parkway. the drivers are following too closely and the driver in the front slows because of traffic to a velocity of 20.0m/s and the driver behind is still moving at 30.0m/s, both cars traveling in the same direction in a rear end collision. if the cars are stuck together after the collision, how fast will they be traveling?

The are moving with a speed of 25 m/s after the collision.

Explanation:

assuming the mass (m) of the cars are equal, let v = 20 m/s be the velocity of the driver in the front and u = 30 m/s be the velocity of the driver behind. let V be the velocity of the cars after the collision.

then, by conservation of linear momentum:

m×(v + u) = V×2×m

(v + u) = V×2

V = (v + u)/2

  = (20 + 30)/2

  = 25 m/s

Therefore, the are moving with a speed of 25 m/s after the collision.

force required to detach it is given by

charges are taken to be fundamental charge

now we have

so above is the minimum distance at which it will detach