Two isolated copper plates, each of area 0.40 m2, carry opposite charges of magnitude 7.08 × 10-10 c. they are placed opposite each other in parallel alignment, with a spacing of 4.0 cm between them. what is the potential difference between the plates? (ε0 = 8.85 × 10-12 c2/n ∙ m2)

The potential difference between the plates is 8 V.

Explanation:

Given that,

Area of plates = 0.40 m²

Charge

Distance = 4.0 cm

We need to calculate the electric field

Using for formula of electric field

Where, q = charge

A = area

Put the value into the formula

We need to calculate the potential difference between the plates

Using formula of potential difference

Where, E = electric field

d = distance

Put the value into the formula

Hence, The potential difference between the plates is 8 V.

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