The fundamental (latex: n=1 n = 1 harmonic or mode) frequency created on a stretched string with fixed ends occurs when the string is driven at a frequency of 50 hz. if the tension in this string is doubled without changing its mass density, what would be the new fundamental frequency?

Explanation:

Given

Fundamental Frequency(f) is 50 Hz

and frequency is given by

Where T= tension

=mass per unit length

if tension is doubled

Divide 1& 2

because it says use -2,0,and 2 for x, we can plug those numbers into the equation. y/4=3/4(-2)+2   y/4= -1 1/2 +2 now to get x by itself, we can multiply each side by 4. y=-6+8 which equals y=2 when x=-2. now you can do the same thing with 0 and 2 as x. you get y=8 when x=0 and y=14 when x=2.

x   |   y

-2 |   2

0   |   8

2   |   14

answer: strength i guess

explanation: