The african cicada is the world's loudest insect, producing a sound intensity level of 107 db at a distance of 0.50 m. what is the intensity of its sound (in w/m2) as heard by someone standing 3.1 m away? express your answer in watts per meter squared.

The intensity of the sound wave is inversely proportional to the distance of the object and source of sound wave.

The intensity of the sound heard by someone standing 3.1 m away is 0.00130 W/m squared.

Intensity of the sound is the intensity flowing per unit area which is perpendicular to the direction of sound wave travelling in.

The intensity of the sound wave is inversely proportional to the distance of the object and source of sound wave.

Given information-

The sound intensity of African cicada insect is 107 dB at a distance of 0.5 m.

The distance of object to hear the sound is 3.1 m.

The application of logarithm function can be used to find the sound level as,

Here, is the intensity of sound level in decibels.

As, the intensity of the sound wave is inversely proportional to the distance of the object and source of sound wave. Thus,

Hence the intensity of the sound heard by someone standing 3.1 m away is 0.00130 W/m squared.

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Explanation:

Given

sound level

fgravity=10x10=100n case 1

fgravity=30x20=600n case 2

6 times more

the answer would be 32*f