Acharged particle beam (shot horizontally) moves into a region where there is a constant magnetic field of magnitude 0.00348 t that points straight down. the charged particles in the beam move in a circular path of radius 1.17 cm. if the charged particles in the beam were accelerated through a potential difference of 110 v, determine the charge to mass ratio of the charged particles in the beam. answer in units of c/kg.

Explanation:

It is given that,

Magnetic field, B = 0.00348 T

Radius of circular path, r = 1.17 cm = 0.0117 m

If the charged particles in the beam were accelerated through a potential difference of 110 V, V = 110 V

Let q is the charge and m is the mass.

The centripetal force is balanced by the magnetic force as :

...........(1)

Also,

Put the value of v in equation (1) as :

So, the charge to mass ratio of the charged particles in the beam is . Hence, this is the required solution.

if they have a finite resultant