The force on a particle is directed along an x axis and given by f = f0(x/x0 - 1) where x is in meters and f is in newtons. if f0 = 0.98 n and x0 = 4.9 m, find the work done by the force in moving the particle from x = 0 to x = 2x0 m.

W = 9.604 J

Explanation:

Given data:

Function of force with respect to displacement (x) as:

F = F₀(x/x₀ - 1)

F₀ = 0.98 N

x₀ = 4.9 m

on substituting the values in the given function, we get

F = 0.98 × [(x/4.9) - 1]

Now, the work done is given as:

W = F . dx

substituting the value of force, we have

W = 0.98 × [(x/4.9) - 1] . dx

on integerating the above formula for the limit x = 0 to x = 2x₀ = 2 × 4.9 = 9.8 m

we get

W =  

or

W =

or

W = 0.98 × [(9.8²/4.9 - 9.8) - 0]

or

W = 9.604 J

find the surface area of the sphere to the nearest square unit. use a calculator.

a. 254 in.2

b. 64 in.2

c. 127 in.2

d. 1,018 in.2

find the sum of the two horizontal vectors and the sum of the two vertical vectors

isoceles right angled triangle