A3.0 kg mass is released from rest at point a. the mass slides along the curved surface to point b in 6.0 seconds. point b is 2.0 m lower than a and the mass is moving at 2.0 m/s at point b. find the average power exerted by kinetic friction on the mass during this segment. a) 0 w b) -3 w c) -6 w d) -9 w e) -18 w

option d) -9 J

Explanation:

Given:

Mass, m = 3.0 kg

time, t = 6.0 seconds

Velocity of mass, v = 2.0 m/s

height, h = 2 m

Now, using the concept of work-Energy theorem

we have

Net work done = change in kinetic energy

or

Work done by gravity + work done by the friction = Final kinetic energy - Initial kinetic energy

mgh + =

on substituting the values in the above equation, we get

3 × 9.8 × 2 + =

or

58.8 + = 6

or

= -52.8 J

here negative sign depicts that the work is done against the motion of the mass

also,

Power = (Work done)/time

or

Power = -52.8/6 = -8.8 W ≈ 9 J

Hence, option d) -9 J is correct

atomic = no of protons.

mass number-atomic number = neutron number

d. learned preferences i believe is your answer