Acoil 4.00 cm in radius, containing 500 turns, is placed in a uniform magnetic field that varies with time according to b = (0.0120 t/s)t + (3.00 x 10-5 t/s4)t4. the coil is connected to a 600 ω resistor, and its plane is perpendicular to the magnetic field. you can ignore the resistance of the coil. what is the current in the resistor at time t = 5.00 s?

The current in the resistor is 1.1304 mA.

Explanation:

Given that,

Radius = 4.00 cm

Number of turns = 500

Magnetic field

Resistance

Time t = 5.00 s

We need to calculate the emf

Using formula of emf

Where, A = area

N = number of turns

B = magnetic field

Put the value into the formula

We need to calculate the current in the resistor at t = 5.00

Using formula of current

Where, R = resistance

Put the value into the formula

Put the value of t in equation (II)

Hence, The current in the resistor is 1.1304 mA.

kinetic

i'm so sorry if this is wrong i'm only in 6th grade xd

i don't understand. explain it clearly