Amonatomic ideal gas has pressure p1 and temperature t1. it is contained in a cylinder of volume v1 with a movable piston, so that it can do work on the outside world. consider the following three-step transformation of the gas: the gas is heated at constant volume until the pressure reaches ap1 (where a> 1). the gas is then expanded at constant temperature until the pressure returns to p1. the gas is then cooled at constant pressure until the volume has returned to v1.
it may be to sketch this process on the pvplane.
how much heat q1 is added to the gas during step 1 of the process?
express the heat added in terms of p1, v1, and a.
how much work w2 is done by the gas during step 2?
express the work done in terms of p1, v1, and a.
how much work w3 is done by the gas during step 3?
if you've drawn a graph of the process, you won't need to calculate an integral to answer this question.
express the work done in terms of p1, v1, and a.

1)

The heat absorbed by the gas can be found by using the 1st law of thermodynamics:

where

is the change in internal energy

Q is the heat absorbed

W is the work done

Since the first process occurs at constant volume, the work done is zero:

So the equation becomes

The change in internal energy is given by

(1)

where

n is the number of moles of the gas, which can be found by using the ideal gas law with the initial conditions of the gas:

(2)

where R is the gas constant,

is the specific heat at constant volume

is the change in temperature. The temperature T2 can calculate again by using the ideal gas law at the new conditions of the gas, after its pressure has reached Ap1:

(3)

Combining (1), (2) and (3), we find:

2)

The work done during an isothermal process is given by:

(4)

where in this case we have:

 (number of moles)

is the constant temperature of the process, found in the previous part

is the final volume, which  can be found again by using the ideal gas law:

is the initial volume

Substituting all the quantities into (4), we find:

3)

Step 3 is an isobatic process (constant pressure), so the work done can be simply calculated as

where:

is the constant pressure of the process

is the final volume

is the initial volume

Substituting into the equation, and keeping in mind that

We find:

answer: 2×10^-2kg

explanation: density= mass per volume

vol=mass/density

converting to s.i units we have;

3÷1000kg = 0.003

1.5÷100m = 0.15

0.003/0.15 = 0.02kg