Imagine that a hypothetical life form is discovered on our moon and transported to earth. on a hot day, this life form begins to sweat, and it is determined that the heat of vaporization of its sweat is 241 cal/g. the scientist observing the extraterrestrial life form also begins to sweat. the heat of vaporization of the scientist's sweat is 580 cal/g at the skin's surface. if both the extraterrestrial life form and the scientist lose 186 g of sweat over the course of one hour, calculate the heat lost by each body from the vaporization of sweat.

131.4 g by strange creature and  54.6 g by scientist

Explanation:

Since the temperature difference between the surroundings and body of both the living beings (average temperature) are the same , amount of heat radiated must have been the same in one hour.

So if we consider X amount of sweat of hypothetical life is vaporized , then amount of sweat for scientist will be (186-X)g.

heat lost by extra-terrestrial life = X x 241 cals

heat lost by scientist = ( 186 - X) x 580 cals

So 241X = ( 186 - X) x580

241X + 580 X = 186 x 580 = 107880

821 X = 107880

X = 131.4 g and 186- 131.4 = 54.6 g .

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