An electromagnetic wave with frequency 65.0 hz travels in an insulating magnetic material that has dielectric constant 3.64 and relative permeability 5.18 at this frequency. the electric field has amplitude 7.20 x 10-3 v/m. what is the amplitude of the magnetic field?

1.04 × 10⁻¹⁰ T

Explanation:

Find the speed of the electromagnetic wave

v=c/√k*kw where;

v= is speed of electromagnetic wave

c=speed of light=3×10⁸

k=dielectric constant=3.64

kw=relative permeability =5.8

v= 3.0×10⁸ / √(3.64×5.8)

v=6.91×10⁷ m/s

Find the amplitude of the electromagnetic wave

Bmax=Emax/v     where

Bmax is amplitude of electromagnetic wave

Emax is Electric field amplitude

v=speed of electromagnetic wave

Bmax=7.20 × 10⁻³ / 6.91×10⁷ = 1.04 × 10⁻¹⁰ T

found in the nucleus

has mass of one amu