A6.0-μf air capacitor is connected across a 100-v battery. after the battery fully charges the capacitor, the capacitor is immersed in transformer oil (dielectric constant = 4.5). how much additional charge flows from the battery, which remained connected during the process?

0.0021 C

Explanation:

First of all, we can calculate the initial charge flowing to the capacitor when it is immersed in air. It is given by

where

is the capacitance

V = 100 V is the potential difference

Substituting,

later, the capacitor is immersed in transformer oil. Therefore, the capacitor can now store a charge equal  to

Q' = kQ

where

k = 4.5 is the dielectric constant of the material

Q is the charge originally stored in the capacitor

Substutitung into the formula, we find

So the additional charge that flows from the battery to the capacitor during the process is

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