You have a 68.3-mf capacitor initially charged to a potential difference of 11.1 v. you discharge the capacitor through a 3.65-ω resistor. what is the time constant? after what multiple of the time constant does the potential difference reach 1.83 v?

0.25 sec

1.8 times

Explanation:

C = Capacitance of the capacitor = 68.3 mF = 68.3 x 10⁻³ F

R = resistance of the resistor = 3.65 Ω

V₀ = Maximum potential difference to which the capacitor is charged = 11.1 Volts

Time constant is given as

T = RC

T = (3.65) (68.3 x 10⁻³)

T = 0.25 sec

V = final potential difference = 1.83 Volts

Using the equation

t = 1.8 T

So 1.8 times

pythagoras' theorem

square root (-5^2+9^2)

square root (25+81)

square root (106)

angle is tan^-1(9/5)

neg x, pos y