The crate, which sets on a 10 degree incline, has a weight of 3433.5 n and is subjected to a towing force p acting at a 20 degree angle with the horizontal. if the coefficient of static friction is µs = 0.5, determine the force p needed to just start the crate moving down the plane.

P = 981 N

Explanation:

Given

Angle of the incline θ = 10°

Angle of the towing force φ =20°

Weight of the crate W = 3433.5 N

The coefficient of static friction µ = 0.5

Solution

Forces Acting along the ramp

Forces acting perpendicular to the ramp

Substituting the value of N we get

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