A2 kg mass hangs motionless from a partially stretched spring having a spring constant of 172 n/m. what is the magnitude of the force (in n) that would be required to pull the mass down by an additional 5 cm? never include units with your answer.

8.608 N

Explanation:

m = 2 kg, K = 172 N/m

Let the extension is x.

F = K x

x = mg / K = 2 x 9.8 / 172 = 0.114 m

now d = 5 cm = 0.05 m

Let additional force is F.

(mg + F) = K (x + d)

(2 x 9.8 + F) = 172(0.114 + 0.05)

19.6 + F = 28.208

F = 8.608 N

0.3x0.21x0.08kg=mass 1 sheet

mass 500 = 500xmass 1

volume pile = 0.3x0.2x0.048

density=mass/volume= 500xmass 1/0.3x0.2x0.048

v patient student

not moving. pos accel,