Astudent is told to use 20.0 g of sodium chloride to make an aqueous solution that has a concentration of 10.0 g/l (grams of sodium chloride per liter of solution). assuming that 20.0 g of sodium chloride has a volume of 7.50 ml, show that she will need about 1.99 l of water to make this solution. in making this solution, should she add the solute to the solvent or the solvent to the solute?

Explanation:

Concentration of sodium chloride = 10.0 g/L

1 Liters of solution has 10 g of sodium chloride

The volume of solution in which 20 g of sodium chloride will present is:

Volume of solution we will be making is of 2 L.

Volume of 20 g of sodium chloride = 7.50 ml = 0.00750 L

Volume of the water = ?

Volume of solution = Volume of solute + Volume of solvent

Volume of solvent = 2L - 0.00750 L = 1.9925 L

So,volume of water required to prepare the 2 L of 10 g/L solution of sodium chloride is 1.9925 L.

And for while making of the solution , student must add solute the solvent.

fgravity=10x10=100n case 1

fgravity=30x20=600n case 2

6 times more

the tires are rotating at 0.434 rpmlinear speed=45 m/sdiameter=0.550 mradius=0.275 mnow v= rωω= v/rω=45/0.275ω=163.6 rad/sω=163.6 rad/s (1rev/2π rad) (60s/1m)ω=1563 rpm