Two teams of nine members each engage in a tug of war. each of the first team’s members has an average mass of 68 kg and exerts an average force of 1350 n horizontally. each of the second team’s members has an average mass of 73 kg and exerts an average force of 1365 n horizontally. what is the tension in the section of rope between the teams?

65.01 N

Explanation:

N = 9

m1 = 68 kg

m2 = 73 kg

F1 = 1350 N towards left

F2 = 1365 N towards right

Fleft = N x F1 = 9 x 1350 = 12150 N

FRight = N x F2 = 9 x 1365 = 12285 N

Fnet  = Fright - Fleft = 12285 - 12150 = 135 N right

Let a be the acceleration

a = Fnet / N(m1 + m2) = 135 / 9(68 + 73) = 0.1064 m/s^2

Let T be the tension in the rope

By the Newton's second law

Fnet - T = 9 m2 x a

135 - T = 9 x 73 x 0.1064

T = 65.01 N

the minimum amperage that the current in this wire would have to have so that its weight is completely supported by the magnetic force due to earth's field, assuming that no other forces except gravity act on it