The safe load, l, of a wooden beam supported at both ends varies jointly as the width, w, the square of the depth, d, and inversely as the length, l. a wooden beam 3in. wide, 6in. deep, and 11ft long holds up 1213lb. what load would a beam 6in. wide, 3in. deep and 12ft long of the same material support? (round off your answer to the nearest pound.)

L' = 555.95 lb

Explanation:

Analyzing the given conditions in the question, we get

The safe load, L is directly proportional to width (w) and square of depth (d²)

 also,

L is inversely proportional length (l) i.e L = k/l

combining the above conditions, we get an equation as:

 L = k(wd²/l)

 now, for the first case we have been given

w = 3 in

d = 6 in

l = 11 ft

L = 1213 lbs

 thus,

1213 lb = k ((3 × 6²)/11)

or

k = 123.54 lbs/(ft.in³)  

Now,

Using the calculated value of k to calculate the value of L in the second case  

in the second case, we have

w = 6 in

d =3 in

l = 12 ft

Final Safe load L' =  123.54 × (6 × 3²/12)

or

L' = 555.95 lb

what are the statements? x

the moon affects the earth gravitation ally, causing certain motions of that body and also producing tides in its ocean and atmosphere. the tidal wave in our atmosphere is, however, far too minute to be an effective cause in any known meteorological phenomenon.

explanation: