Aball is attached to the end of a string of length l, forming a pendulum. the period of the pendulum is 4.0 s. if the length of the string is doubled, now what is the period of oscillation?

The period of oscillation when the lenght of the string is doubled is: T= 5.65 sec.

Explanation:

T1= 4s

L1=?

L2= 2L1=

T2= ?

g= 9.8 m/s²

T1= 2π √(L1/g)

clearing L1:

L1= 3.97m

L2= 7.94m

T2= 2π √(L2/g)

T2= 5.65 s

50 inches should be the resultant vector

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