The a string on a violin has a fundamental frequency of 440 hz. the length of the vibrating portion is 32 cm, and it has mass 0.35 g. under what tension must the string be placed?

86.75 N

Explanation:

f = 440 Hz

l = 32 cm = 0.32 m

m = 0.35 g = 0.35 x 10^-3 kg

μ = m / l = 0.35 x 10^-3 / 0.32 = 1.094 x 10^-3 kg/m

The formula for the fundamental frequency is given by

Where, T be the tension

T = 86.75 N

Thus, the tension in the string is 86.75 N.

acceleration = (change in speed) / (time for the change)

change in speed = (20-120)= -100 m/s.

1.5 min = 90 sec

acceleration = -100/90 = -1.11 m/s^2.

we don't care about the 150kg or the 2,500 meters. they don't make any difference.

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because growing process had stoped after 4-5 year