A2 ev electron encounters a barrier 5.0 ev high and width a. what is the probability b) 0.5 that it will tunnel through the barrier if the barrier width a is (a) 1.00 nm [5p nm 5pt]? suggestion: use t as given in lecture 9-10

The tunnel probability for 0.5 nm and 1.00 nm are   and respectively.

Explanation:

Given that,

Energy E = 2 eV

Barrier V₀= 5.0 eV

Width = 1.00 nm

We need to calculate the value of

Using formula of

Put the value into the formula

(a). We need to calculate the tunnel probability for width 0.5 nm

Using formula of tunnel barrier

Put the value into the formula

(b). We need to calculate the tunnel probability for width 1.00 nm

Hence, The tunnel probability for 0.5 nm and 1.00 nm are   and respectively.

the chart show the masses and velocities of two colliding objects that stick together after a collision.

according to the law of conservation of momentum, the momentum of the object after the collision is  

answer

1,500

kg • m/s.