Ablock of density pb = 9.50 times 10^2 kg/m^3 floats face down in a fluid of density pt = 1.30 times 10^3 kg/m^3. the block has height h = 8.00 cm. by what depth ft is the block submerged? if the block is held fully submerged and then released, what is the magnitude of its acceleration?

The depth and acceleration are 0.1919291 ft and 3.61 m/s².

Explanation:

Given that,

Density of block

Density of fluid

We need to calculate the depth

Using balance equation

....(I)

We know that,

The density is

Put the value of m in equation (I)

Put the value into the formula

We need to calculate the acceleration

Using formula of net force

....(II)

Put the value in the equation (II)

Hence, The depth and acceleration are 0.1919291 ft and 3.61 m/s².

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