Ameter stick whose mass is 310 grams lies on ice. you pull at one end of the meter stick, at right angles to the stick, with a force f = 9 newtons. the ensuing motion of the meter stick is quite complicated, but what are the initial magnitude and direction of the rate of change of the momentum of the stick, dptot/dt, when you first apply the force?

and the direction of change of momentum will be in the direction of the applied force.

Explanation:

Given data in the question:

mass of the meter stick, ma = 310 grams

Applied force on the stick, F = 9 Newtons

Now, from the Newton's second law of motion we have

Net force = change in momentum per unit change in time

or

or

and the direction of change of momentum will be in the direction of the applied force.

d₁ = displacement of tern from arctic to antarctic = 11000 miles

d₂ = displacement of tern from antarctic to arctic =   - 11000 miles

d = total displacement for the journey

total displacement for the journey is given as

d = d₁ + d₂

d = 11000 + (-11000)

d = 0 miles

t₁ = time of travel from arctic to antarctic = 3 months = 3 x 30 days = 90 days

t₂ = time of travel from antarctic to arctic = 3 months = 3 x 30 days = 90 days

t = total time of travel

total time of travel is given as

t = t₁ + t₂

t = 90 + 90

t = 180 days

average velocity is given as

average velocity = total displacement/ total time

v = d/t

v = 0/180

v = 0 miles/day

at right angles to each other