Ameteorite has a speed of 95.0 m/s when 750 km above the earth. it is falling vertically (ignore air resistance) and strikes a bed of sand in which it is brought to rest in 3.35 m . part a what is its speed just before striking the sand?

3.83 km/s.

Explanation:

u = 95 m/s, h = 750 km = 750,000 m

Let the speed is v as it strikes the sand.

Use third equation of motion

v^2 = u^2 + 2 g h

v^2 = 95^2 + 2 x 9.8 x 750000

v^2 = 9025 + 14700000 = 14709025

v = 3835.23 m /s = 3.83 km /s

Thus, the speed of the meteorite as it strikes t sand is 3.83 km/s.

increase masses, decrease separation