The spring-held follower ab has a weight of 0.83 lb and moves back and forth as its end rolls on the contoured surface of the cam, where r = 0.2 ft and latex: z=\left(0.1\sin2\theta\right) z = ( 0.1 sin ⁡ 2 θ ) ft. if the cam is rotating at a constant rate of 5 rad/s, determine the force at the end a of the follower when latex: \theta=45^\circ θ = 45 ∘ . in this position the spring is compressed 0.4 ft. neglect friction at the bearing c.

i believe the answer is a

insects!

explanation:

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i just did this and got a 100.

energy stored in the capacitor= 9.72 x 10⁻⁴ j

explanation:

the energy stored in the capacitor is given by

e= 1/2 c v²

e= energy stored

c= capacitance= 1.5 µc= 1.5 x 10⁻⁶f

v= potential difference=36 v

so energy stored= e= 1/2 (1.5 x 10⁻⁶) (36)²

energy stored= 9.72 x 10⁻⁴j