If an object is dropped from a tall building and it hits the ground 3.0 s later, what is the velocity of the object when it hits the ground? (remember that the velocity is downward)
v= m/s

-29.4 m/s

Explanation:

Initial velocity is 0 m/s.

Acceleration is -9.8 m/s².

Time is 3.0 s.

v = at + v₀

v = (-9.8)(3.0) + 0

v = -29.4 m/s

moving ball hits still ball. mover stops, hit ball moves. momentum transfer.

at right angles to each other