Ameter stick is pivoted at the 0.50-m line. a 3.0-kg object is hung from the 0.15-m line. where should a 5.0-kg object be hung to achieve equilibrium (the meter stick oriented horizontal and motionless)?

0.71 m

Explanation:

Let the 5 kg is hang at a distance d from the midpoint.

use the concept of moments.

take moments about the mid point.

Anticlockwise moments = clockwise moments

3 x (0.5 - 0.15) = 5 x d

1.05 = 5 d

d = 0.21 m

So, the distance of 5 kg from 0 mark on the stick is 0.5 + 0.21 = 0.71 m

this is poiselle's equation from fluid mechanic in physics. mech eng

  distance on the y-axis and time on the x-axis.

explanation:

the instantaneous velocity = change in position/time taken

the slope of the graph should give instantaneous velocity.

  slope of a graph = change in value of y -axis / change in values of x -axis

  comparing both the equations

    change in value of y -axis = change in position

  change in values of x -axis = time taken

so position values should be on the y axis and time values should be on the x axis.

distance on the y-axis and time on the x-axis.