Acoil of conducting wire carries a current i. in a time interval of δt = 0.520 s, the current goes from i1 = 3.20 a to i2 = 1.90 a. the average emf induced in the coil is e m f = 14.0 mv. assuming the current does not change direction, calculate the coil's inductance (in mh).

5.6 mH

Explanation:

i1 = 3.20 A, i2 = 1.90 A, e = 14 mV = 0.014 V,

Let L be the coil's inductance.

L = 0.0056 H

L = 5.6 mH

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