Abox rests on the (horizontal) back of a truck. the coefficient of static friction between the box and the surface on which it rests is 0.24. what maximum distance can the truck travel (starting from rest and moving horizontally with constant acceleration) in 3.0 s without having the box slide?

The distance is 11 m.

Explanation:

Given that,

Friction coefficient = 0.24

Time = 3.0 s

Initial velocity = 0

We need to calculate the acceleration

Using newton's second law

...(I)

Using formula of friction force

....(II)

Put the value of F in the equation (II) from equation (I)

....(III)

Put the value in the equation (III)

We need to calculate the distance,

Using equation of motion

Hence, The distance is 11 m.

here we know that ball will drop down by total distance 3.2 m

so here we know that

now using kinematics

now in the same time it will cover horizontal distance of 0.75 m

so speed of the ball will be

cant without the picture! ?