The electric field at a point 2.8 cm from a small object points toward the object with a strength of 180,000 n/c. what is the object's charge q? ( k = 1/4πε 0 = 8.99 × 10 9 n ∙ m 2/c 2)

Charge,

Explanation:

It is given that,

Electric field strength, E = 180000 N/C

Distance from a small object, r = 2.8 cm = 0.028 m

Electric field at a point is given by :

Q is the charge on an object

So, the charge on the object is . Hence, this is the required solution.

double the distance = divide strength by 4

does anyone know or what?