The electric flux through a square-shaped area of side 5 cm near a large charged sheet is found to be 3 × 10−5 n · m2 /c when the area is parallel to the plate. find the charge density on the sheet.

Explanation:

Given:

Electric Flux =

Side of sheet = 5cm

Area of the square sheet, A= 5×5 = 25cm²=25×10⁻⁴ m²

Now

the electric flux (Φ) is given as:

where, E = Electric field

or

substituting the values in the above equation, we get

Now the charge density (σ) on a sheet is given as:

where, = Permittivity of the free space = 8.85×10⁻¹²

substituting the values in the above equation, we get

your answer would be fusion

the answer is b

explanation: