Work is required to compress 5.00 mol of air at 20.00c and 1.00 atm to one-tenth of the original volume by an adiabatic process. how much work is required to produce this same compression?

46.03 KJ

Explanation:

no of moles(n)=5

temperature of air(T)=

pressure(p)=1 atm

final volume is

We know work done in adaibatic process is given by

W=

for air is 1.4

we know

=

W=

W=-46.03 KJ

it means work is done on the system

explanation:

could i give you a exaplo that could you?

hi i’m sorry to call us today so we will get back with y’all and we will have to do it haha omg was the day