A92.0kg baseball player slides into second base. the coefficient of friction between the player and the ground is 0.61. if the player comes to rest after 1.2s, what was his initial speed?

The initial speed is 7.174 m/s.

Explanation:

Given that,

Mass = 92.0 kg

Coefficient of friction = 0.61

Time = 1.2 s

We need to calculate the acceleration

Using of friction force

...(I)

Where, =Coefficient of friction

g = acceleration due to gravity

Using newton's law

....(II)

m = mass of the baseball

a = acceleration of the baseball

From equation (I) and (II)

...(I)

Put the value in the equation

We need to calculate the initial velocity

Using equation of motion

Where, v = final velocity

u = initial velocity

a = acceleration

Here, a is negative because the player comes to rest

t = time

Put the value in the equation

Hence, The initial speed is 7.174 m/s.

what are the statements? x

the working equation for the angular size is the product of the physical size and 360 degrees divided by the product of two pi and distance from earth. the minimum size would be 0.559 degrees while the maximum size would be 0.49 degrees.