Determine the average value of the translational kinetic energy of the molecules of an ideal gas at (a) 27.8°c and (b) 143°c. what is the translational kinetic energy per mole of an ideal gas at (c) 27.8°c and (d) 143°c?

a)

b)

c)  

d)  

Explanation:

Average translation kinetic energy () is given as

   ....................(1)

where,

k = Boltzmann's constant ; 1.38 × 10⁻²³ J/K

T = Temperature in kelvin

a) at T = 27.8° C

or

T = 27.8 + 273 = 300.8 K

substituting the value of temperature in the equation (1)

we have

b) at T = 143° C

or

T = 143 + 273 = 416 K

substituting the value of temperature in the equation (1)

we have

c ) The translational kinetic energy per mole of an ideal gas is given as:

here   = Avagadro's number; ( 6.02×10²³ )

now at T = 27.8° C

d) now at T = 143° C

work: w = fd (given)

work done by chet   =50*1 = 50 j

work done by mika =40*2 = 80 j

work done by sara =30*1.5 = 45 j

work done by bill =60*0.5 = 30 j

students in order from the greatest amount of work done to the least is mika> chet> sara> bill

hence option (b) is correct.

50 inches should be the resultant vector